Welcome to Tracey P.'s Math Analysis Blog

Sunday, September 29, 2013

SV#1: Unit F Concept 10 - Finding all real and imaginary zeroes of a polynomial

To view my video, please click on the link HERE.

This video will show you how to find the zeroes and factorizations for a fourth or fifth degree polynomial. It will show you each step you would need to take to find the zeroes of a polynomial.

While watching this video, be sure to pay close attention to each steps. Also, remember to use the Descartes Rule of Signs when solving for the polynomial. Remember to double-check your answers and see if each steps are correct.

Monday, September 16, 2013

SP#2: Unit E Concept 7 - Graphing a polynomial and identifying all key parts

This picture will show you how to find the end behavior as well as the x intercepts and multiplicities. You will also learn how to tell if the graph will go "Thru", "Bounce", or "Curve". The picture shows the basic steps of how to sketch a graph based on multiplicities and x intercepts.

The first step to solve this equation is to factor out the equation. Once you have done that, the answer should be: (x-2)(x-2)(x+2)(x+1). As you can tell from the equation, it is even positive. This means that both the end points go upwards. To find the x intercepts, you put each factor equal to zero. The answers should be: (2,0) M2, (-2,0) M1, (-1,0) M1. Next, you find the y intercept is 8 because you substitute all the X's for 0's; the answer should be: (0,8). To graph it, you look at the multiplicities if it's a multiplicity of one, then it's through. If it's a multiplicity of 2, then the graph bounces and if it's a multiplicity of 3, it's curving.

Monday, September 9, 2013

SP#1: Unit E Concept 1 - Graphing a quadratic and identifying all key parts

This problem is showing how to find x-intercepts, y-intercepts, and the vertex (Maximum/minimum).
~Completing the Square~
In this problem, I first added 8 to the other side of the equation. Then,I took out a four and put it outside of the parenthesis. I then divided by 4. After,I square rooted everything and subtracted 2 to the other side. Because the equation is positive, it will be a minimum. The axis of symmetry will be at -2. To find y-int, you substitute 0 in for x, and find that it's -8.